What is x-y+x^2+y^2-1=0 ?

The solution to x-y+x^2+y^2-1=0 is Circle with (a,b)=(-1/2 , 1/2),r=sqrt(3/2)

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x-y+x^2+y^2-1=0

x - y + x^{2} + y^{2} - 1 = 0

(a, b) = (- \frac{1}{2}, \frac{1}{2}), r = \frac{3}{2}

Solution steps

x - y + x^{2} + y^{2} - 1 = 0

Rewrite

x - y + x^{2} + y^{2} - 1 = 0

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - \frac{1}{2})^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, \frac{1}{2}), r = \frac{3}{2}

x^{2} + y^{2} = 4^{2}

x, p (x)^{2} + x^{2} = 25

x^{2} + (y - 3)^{2} = 81

(x - 5)^{2} + y^{2} = 25

4 x^{2} - 12 x + 4 y^{2} + 16 y - 5 = 0

What is x-y+x^2+y^2-1=0 ?
The solution to x-y+x^2+y^2-1=0 is Circle with (a,b)=(-1/2 , 1/2),r=sqrt(3/2)