What is x^2+y^2-14x+2y=14 ?

The solution to x^2+y^2-14x+2y=14 is Circle with (a,b)=(7,-1),r=8

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x^2+y^2-14x+2y=14

x^{2} + y^{2} - 14 x + 2 y = 14

(a, b) = (7, - 1), r = 8

Solution steps

x^{2} + y^{2} - 14 x + 2 y = 14

Rewrite

x^{2} + y^{2} - 14 x + 2 y = 14

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 1))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (7, - 1), r = 8

(x + 3)^{2} + (y - 1)^{2} = 64

x^{2} + y^{2} + 2 x - 6 y + 5 = 0

x^{2} + y^{2} - 6 x + 4 y - 20 = 0

2 (x + 6)^{2} + 2 (y + 9)^{2} = 50

2 x^{2} + 2 y^{2} + 16 y + 14 = 0

What is x^2+y^2-14x+2y=14 ?
The solution to x^2+y^2-14x+2y=14 is Circle with (a,b)=(7,-1),r=8