What is (x+7)^2+(y+8)^2= 4/9 ?

The solution to (x+7)^2+(y+8)^2= 4/9 is Circle with (a,b)=(-7,-8),r= 2/3

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(x+7)^2+(y+8)^2= 4/9

(x + 7)^{2} + (y + 8)^{2} = \frac{4}{9}

(a, b) = (- 7, - 8), r = \frac{2}{3}

Solution steps

(x + 7)^{2} + (y + 8)^{2} = \frac{4}{9}

Rewrite

(x + 7)^{2} + (y + 8)^{2} = \frac{4}{9}

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 8))^{2} = (\frac{2}{3})^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 8), r = \frac{2}{3}

2 y + 13 + x^{2} = 8 x - y^{2}

2 x^{2} + 2 y^{2} + 8 x - 6 y + 4 = 0

(x - 5)^{2} + (y + 2)^{2} = 9

x^{2} + y^{2} = 85

(x - 1)^{2} + (y - 2)^{2} = 81

What is (x+7)^2+(y+8)^2= 4/9 ?
The solution to (x+7)^2+(y+8)^2= 4/9 is Circle with (a,b)=(-7,-8),r= 2/3