What is x^2+(y-10)^2=10 ?

The solution to x^2+(y-10)^2=10 is Circle with (a,b)=(0,10),r=sqrt(10)

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x^2+(y-10)^2=10

x^{2} + (y - 10)^{2} = 10

(a, b) = (0, 10), r = 10

Solution steps

x^{2} + (y - 10)^{2} = 10

Rewrite

x^{2} + (y - 10)^{2} = 10

in the form of the standard circle equation

(x - 0)^{2} + (y - 10)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (0, 10), r = 10

x^{2} + y^{2} - 6 x - 6 y + 9 = 0

x^{2} + y^{2} - 4 x + 10 y + 25 = 0

(x + 3)^{2} + (y + \frac{5}{4})^{2} = (\frac{11}{2})^{2}

(x + 3)^{2} + (y + 5)^{2} = 9

(x + 2)^{(2)} + (y - 1)^{(2)} = 16

What is x^2+(y-10)^2=10 ?
The solution to x^2+(y-10)^2=10 is Circle with (a,b)=(0,10),r=sqrt(10)