What is (x-11)^2+(y+7)^2=144 ?

The solution to (x-11)^2+(y+7)^2=144 is Circle with (a,b)=(11,-7),r=12

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(x-11)^2+(y+7)^2=144

(x - 11)^{2} + (y + 7)^{2} = 144

(a, b) = (11, - 7), r = 12

Solution steps

(x - 11)^{2} + (y + 7)^{2} = 144

Rewrite

(x - 11)^{2} + (y + 7)^{2} = 144

in the form of the standard circle equation

(x - 11)^{2} + (y - (- 7))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (11, - 7), r = 12

x^{2} + y^{2} - 16 x + 12 y + 64 = 0

x^{2} = 9 - y^{2}

x^{2} + y^{2} - \frac{1}{4} x + \frac{1}{4} y = \frac{1}{32}

x^{2} + y^{2} - 4 x - 14 y - 28 = 0

(x + 4)^{2} + (y - 3)^{2} = 1

What is (x-11)^2+(y+7)^2=144 ?
The solution to (x-11)^2+(y+7)^2=144 is Circle with (a,b)=(11,-7),r=12