What is 9x^2+9y^2+72x-12y+103=0 ?

The solution to 9x^2+9y^2+72x-12y+103=0 is Circle with (a,b)=(-4, 2/3),r=sqrt(5)

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9x^2+9y^2+72x-12y+103=0

9 x^{2} + 9 y^{2} + 72 x - 12 y + 103 = 0

(a, b) = (- 4, \frac{2}{3}), r = 5

Solution steps

9 x^{2} + 9 y^{2} + 72 x - 12 y + 103 = 0

Rewrite

9 x^{2} + 9 y^{2} + 72 x - 12 y + 103 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - \frac{2}{3})^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 4, \frac{2}{3}), r = 5

9 x^{2} + 9 y^{2} - 12 x + 36 y - 104 = 0

x^{2} + 4 x + y^{2} - 4 y = 1

2 x^{2} + 2 y^{2} + x + y = 0

(x + 3)^{2} + (y - 2)^{2} = 1

9 x^{2} + 9 y^{2} = 16

What is 9x^2+9y^2+72x-12y+103=0 ?
The solution to 9x^2+9y^2+72x-12y+103=0 is Circle with (a,b)=(-4, 2/3),r=sqrt(5)