What is x^2+y^2-18x+16y+120=0 ?

The solution to x^2+y^2-18x+16y+120=0 is Circle with (a,b)=(9,-8),r=5

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x^2+y^2-18x+16y+120=0

x^{2} + y^{2} - 18 x + 16 y + 120 = 0

(a, b) = (9, - 8), r = 5

Solution steps

x^{2} + y^{2} - 18 x + 16 y + 120 = 0

Rewrite

x^{2} + y^{2} - 18 x + 16 y + 120 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 8))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (9, - 8), r = 5

x^{2} + y^{2} + 8 x - 12 y + 47 = 0

x^{2} + y^{2} - 3 x + 6 y + 9 = 0

x^{2} + y^{2} - 8 x + 6 y - 24 = 0

3 x^{2} + 3 y^{2} - 30 x - 36 y - 9 = 0

x^{2} + y^{2} - 8 x + 10 y = 128

What is x^2+y^2-18x+16y+120=0 ?
The solution to x^2+y^2-18x+16y+120=0 is Circle with (a,b)=(9,-8),r=5