What is -11=-4y^2-4y-4x^2 ?

The solution to -11=-4y^2-4y-4x^2 is Circle with (a,b)=(0,-1/2),r=sqrt(3)

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-11=-4y^2-4y-4x^2

- 11 = - 4 y^{2} - 4 y - 4 x^{2}

(a, b) = (0, - \frac{1}{2}), r = 3

Solution steps

- 11 = - 4 y^{2} - 4 y - 4 x^{2}

Rewrite

- 11 = - 4 y^{2} - 4 y - 4 x^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - (- \frac{1}{2}))^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (0, - \frac{1}{2}), r = 3

x^{2} + y^{2} - x + 4 y + 4 = 0

(x - 1)^{2} + (y - 1)^{2} = 25

x^{2} + y^{2} - 10 x - 6 y - 30 = 0

x^{2} + y^{2} - 14 x + 8 y + 61 = 0

x^{2} + y^{2} - 2 x + 10 y - 55 = 0

What is -11=-4y^2-4y-4x^2 ?
The solution to -11=-4y^2-4y-4x^2 is Circle with (a,b)=(0,-1/2),r=sqrt(3)