What is (x+2)^2+y^2=36 ?

The solution to (x+2)^2+y^2=36 is Circle with (a,b)=(-2,0),r=6

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(x+2)^2+y^2=36

(x + 2)^{2} + y^{2} = 36

(a, b) = (- 2, 0), r = 6

Solution steps

(x + 2)^{2} + y^{2} = 36

Rewrite

(x + 2)^{2} + y^{2} = 36

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 2, 0), r = 6

x^{2} + (y - 3960)^{2} = 396 0^{2}

a^{2} + b^{2} = 9

x^{2} + y^{2} - 2 \cdot x - 4 \cdot y + 1 = 0

4 x^{2} + 48 x + 4 y^{2} = 0

x^{2} + y^{2} + 8 y + 12 = 0

What is (x+2)^2+y^2=36 ?
The solution to (x+2)^2+y^2=36 is Circle with (a,b)=(-2,0),r=6