What is 4y^2+4x^2-24x+35=0 ?

The solution to 4y^2+4x^2-24x+35=0 is Circle with (a,b)=(3,0),r= 1/2

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4y^2+4x^2-24x+35=0

4 y^{2} + 4 x^{2} - 24 x + 35 = 0

(a, b) = (3, 0), r = \frac{1}{2}

Solution steps

4 y^{2} + 4 x^{2} - 24 x + 35 = 0

Rewrite

4 y^{2} + 4 x^{2} - 24 x + 35 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = \frac{1}{2}

x^{2} + y^{2} + 10 x + 14 y = - 70

x^{2} + y^{2} - 6 x - 4 y - 15 = 0

y^{2} = 7 - x^{2}

(x - 1)^{2} + (y + 3)^{2} - 9 = 0

(x + 1)^{2} + (y + 3)^{2} = 5

What is 4y^2+4x^2-24x+35=0 ?
The solution to 4y^2+4x^2-24x+35=0 is Circle with (a,b)=(3,0),r= 1/2