What is x^2+y^2+10x-8y+25=0 ?

The solution to x^2+y^2+10x-8y+25=0 is Circle with (a,b)=(-5,4),r=4

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x^2+y^2+10x-8y+25=0

x^{2} + y^{2} + 10 x - 8 y + 25 = 0

(a, b) = (- 5, 4), r = 4

Solution steps

x^{2} + y^{2} + 10 x - 8 y + 25 = 0

Rewrite

x^{2} + y^{2} + 10 x - 8 y + 25 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 4)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 5, 4), r = 4

3 x^{2} + 3 y^{2} - 48 x + 144 = 0

x^{2} + y^{2} - 10 x + 4 y + 20 = 0

(x - 0)^{2} + (y - 0)^{2} = 16

(x - 3)^{2} + (y - 5)^{2} = 16

x^{2} + y^{2} = \frac{25}{36}

What is x^2+y^2+10x-8y+25=0 ?
The solution to x^2+y^2+10x-8y+25=0 is Circle with (a,b)=(-5,4),r=4