What is 2x^2+2y^2+10x-6y-55=0 ?

The solution to 2x^2+2y^2+10x-6y-55=0 is Circle with (a,b)=(-5/2 , 3/2),r=6

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2x^2+2y^2+10x-6y-55=0

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

(a, b) = (- \frac{5}{2}, \frac{3}{2}), r = 6

Solution steps

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

Rewrite

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{3}{2})^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{3}{2}), r = 6

x^{2} + y^{2} - 8 y + 7 = 0

(x - 4)^{2} + (y - 2)^{2} = 9

x^{2} + y^{2} - 10 x + 6 y - 66 = 0

x^{2} + y^{2} + 2 x + y + 1 = 0

x^{2} + y^{2} + 14 x - 10 y + 65 = 0

What is 2x^2+2y^2+10x-6y-55=0 ?
The solution to 2x^2+2y^2+10x-6y-55=0 is Circle with (a,b)=(-5/2 , 3/2),r=6