What is the range of f(x)= 1/(sqrt(x-6)) ?

The range of f(x)= 1/(sqrt(x-6)) is f(x)>0

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range of f(x)= 1/(sqrt(x-6))

range

f (x) = \frac{1}{x - 6}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{1}{x - 6} : x > 6

Extreme Points of

\frac{1}{x - 6} :

None

Find the range for the interval

6 < x < \infty : 0 < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) > 0

- x - 5

f (x) = lo g_{5} (12 - 4 x)

y = x + 4

3 x + 9

f (x) = \frac{t - 5}{3 t - 18}

What is the range of f(x)= 1/(sqrt(x-6)) ?
The range of f(x)= 1/(sqrt(x-6)) is f(x)>0