What is the domain of f(x)=(x+1)^2-9 ?

The domain of f(x)=(x+1)^2-9 is -infinity <x<infinity

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domain of f(x)=(x+1)^2-9

domain

f (x) = (x + 1)^{2} - 9

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{1}{2 + e ^{2 x}}

f (x) = 3^{x} + 1

m = \frac{2}{3}, (9, - 1)

6 x - x^{2} + 7

f (x) = ∣ 2 x - 8 ∣

What is the domain of f(x)=(x+1)^2-9 ?
The domain of f(x)=(x+1)^2-9 is -infinity <x<infinity