What is the domain of f(x)=(9x)/(sqrt(x+9)) ?

The domain of f(x)=(9x)/(sqrt(x+9)) is x>-9

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domain of f(x)=(9x)/(sqrt(x+9))

domain

f (x) = \frac{9 x}{x + 9}

x > - 9

Interval Notation

(- 9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = - 9

Combine real regions and undefined points for final function domain

x > - 9

f (x) = 3 x^{2} - \frac{10}{x}

f (x) = \frac{2}{x + 5}

- 4

\frac{7 x}{x + 3} - 3

9 x + 7 y = - 5

What is the domain of f(x)=(9x)/(sqrt(x+9)) ?
The domain of f(x)=(9x)/(sqrt(x+9)) is x>-9