What is the domain of f(x)=(9x^2+x)/(x^2+4) ?

The domain of f(x)=(9x^2+x)/(x^2+4) is -infinity <x<infinity

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domain of f(x)=(9x^2+x)/(x^2+4)

domain

f (x) = \frac{9 x ^{2} + x}{x ^{2} + 4}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = - (\frac{1}{3})^{x} + 2

f (x) = 3^{x} - 1

f (x) = \frac{( - x ^{2} + 8 )}{( 2 x ^{2} - 3 )}

f (x) = \frac{x}{x ^{2} + 16}

f (x) = 4 x^{2} + 16 y^{2} = 64

What is the domain of f(x)=(9x^2+x)/(x^2+4) ?
The domain of f(x)=(9x^2+x)/(x^2+4) is -infinity <x<infinity