What is the domain of f(x)=x*sin(1/(x^2)) ?

The domain of f(x)=x*sin(1/(x^2)) is x 0

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domain of f(x)=x*sin(1/(x^2))

domain

f (x) = x \cdot sin (\frac{1}{x ^{2}})

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

y = - 7 x + 5

y = 3 x^{2} + 4 x - 5

f (x) = x^{2} - 5 x + 6

f (x) = 7 x^{3} + 4

f (x) = 0.25 x + 40

What is the domain of f(x)=x*sin(1/(x^2)) ?
The domain of f(x)=x*sin(1/(x^2)) is x<0\lor x>0