What is the domain of f(x)=sqrt(3+2x) ?

The domain of f(x)=sqrt(3+2x) is x>=-3/2

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domain of f(x)=sqrt(3+2x)

domain

f (x) = 3 + 2 x

x \geq - \frac{3}{2}

Interval Notation

[- \frac{3}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{3}{2}

The function domain

x \geq - \frac{3}{2}

\frac{x ^{2} + 4 x - 5}{x - 1}

\frac{8 x}{7 x - 3}

f (x) = \frac{1}{x - 1} + \frac{1}{x - 2}

f (x) = \frac{x ^{2}}{x - 8}

\frac{2 x ^{4} - x ^{2} + 1}{x ^{2} - 4}

What is the domain of f(x)=sqrt(3+2x) ?
The domain of f(x)=sqrt(3+2x) is x>=-3/2