What is the range of 1/4 tan(1/8 x)-2 ?

The range of 1/4 tan(1/8 x)-2 is -infinity <f(x)<infinity

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range of 1/4 tan(1/8 x)-2

range

\frac{1}{4} tan (\frac{1}{8} x) - 2

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of the basic

tan

function is

- \infty < tan (\frac{1}{8} x) < \infty

- \infty < tan (\frac{1}{8} x) < \infty

Multiply the edges of the range by:

\frac{1}{4}

- \infty < \frac{1}{4} tan (\frac{1}{8} x) < \infty

Add to the edges of the range:

- 2

- \infty < \frac{1}{4} tan (\frac{1}{8} x) - 2 < \infty

Therefore the range is

- \infty < f (x) < \infty

f (x) = \frac{x - 2}{( x + 2 ) ( x - 2 )}

f (x) = x^{2} - 8 x + 20

f (x) = \frac{4 x ^{2} - 1}{∣ 2 x + 1 ∣}

y = x + 6

f (x) = 9 - 3 x

What is the range of 1/4 tan(1/8 x)-2 ?
The range of 1/4 tan(1/8 x)-2 is -infinity <f(x)<infinity