What is the domain of 9/(x^2-1)+1 ?

The domain of 9/(x^2-1)+1 is x 1

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domain of 9/(x^2-1)+1

domain

\frac{9}{x ^{2} - 1} + 1

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = lo g_{2} (3 - ∣ 1 - x ∣)

\frac{100000}{100 + 900 e ^{- t}}

\frac{9 x}{3 - x}

What is the domain of 9/(x^2-1)+1 ?
The domain of 9/(x^2-1)+1 is x<-1\lor-1<x<1\lor x>1