What is the range of R(x)=3+cos(2x) ?

The range of R(x)=3+cos(2x) is 2<= f(x)<= 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of R(x)=3+cos(2x)

range

R (x) = 3 + cos (2 x)

2 \leq f (x) \leq 4

Interval Notation

[2, 4]

Solution steps

The range of the basic

cos

function is

- 1 \leq cos (2 x) \leq 1

- 1 \leq cos (2 x) \leq 1

Add to the edges of the range:

3

2 \leq cos (2 x) + 3 \leq 4

Therefore the range is

2 \leq f (x) \leq 4

f (x) = \frac{4 x - 24}{2 x - 4}

f (x) = \frac{x ^{2} - 4}{3 x ^{2}}

5.75 cos (\frac{π}{3} t) + 7.88

y = x^{4} - 4 x^{3} + 10

f (x) = \frac{- 2}{x + 2}

What is the range of R(x)=3+cos(2x) ?
The range of R(x)=3+cos(2x) is 2<= f(x)<= 4