What is the domain of f(x)=(2x+1)/(x^2-49) ?

The domain of f(x)=(2x+1)/(x^2-49) is x 7

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domain of f(x)=(2x+1)/(x^2-49)

domain

f (x) = \frac{2 x + 1}{x ^{2} - 49}

x < - 7 or - 7 < x < 7 or x > 7

Interval Notation

(- \infty, - 7) \cup (- 7, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 7

The function domain

x < - 7 or - 7 < x < 7 or x > 7

f (x) = 2

e^{4 x}

f (x) = ln (x - 3)

- x^{2} + 4 x - 4

f (x) = 3 x - y = 9

What is the domain of f(x)=(2x+1)/(x^2-49) ?
The domain of f(x)=(2x+1)/(x^2-49) is x<-7\lor-7<x<7\lor x>7