What is the domain of f(x)=sqrt(x^3-9x^2-x+9) ?

The domain of f(x)=sqrt(x^3-9x^2-x+9) is -1 = 9

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domain of f(x)=sqrt(x^3-9x^2-x+9)

domain

f (x) = x^{3} - 9 x^{2} - x + 9

- 1 \leq x \leq 1 or x \geq 9

Interval Notation

[- 1, 1] \cup [9, \infty)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1 or x \geq 9

The function domain

- 1 \leq x \leq 1 or x \geq 9

- 4 x^{4} + 5 x^{3} - x^{2}

5 x^{3} - 5 x^{2} - 4

f (x) = 8 x

f (x) = 2 - 5 x

cos (4 x)

What is the domain of f(x)=sqrt(x^3-9x^2-x+9) ?
The domain of f(x)=sqrt(x^3-9x^2-x+9) is -1<= x<= 1\lor x>= 9