What is the domain of f(x)= 5/(2x^2+1) ?

The domain of f(x)= 5/(2x^2+1) is -infinity <x<infinity

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domain of f(x)= 5/(2x^2+1)

domain

f (x) = \frac{5}{2 x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

m = 3, (- 3, 0)

ln (x + 4)

f (x) = (\frac{2}{5})^{x + 2} - 1

f (x) = - x + 7

(- 16, 2), (4, - 11)

What is the domain of f(x)= 5/(2x^2+1) ?
The domain of f(x)= 5/(2x^2+1) is -infinity <x<infinity