What is the domain of f(x)=sqrt((2x-4)/3) ?

The domain of f(x)=sqrt((2x-4)/3) is x>= 2

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domain of f(x)=sqrt((2x-4)/3)

domain

f (x) = \frac{2 x - 4}{3}

x \geq 2

Interval Notation

[2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

The function domain

x \geq 2

\frac{7}{x}

(0, 2), (1, 1)

f (x) = sin (π x)

f (x) = 7 x^{2} + 9 y = 63

f (x) = 2 x^{2} + 1 - x

What is the domain of f(x)=sqrt((2x-4)/3) ?
The domain of f(x)=sqrt((2x-4)/3) is x>= 2