What is the domain of (x^2-5x-6)/(x+1) ?

The domain of (x^2-5x-6)/(x+1) is x -1

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domain of (x^2-5x-6)/(x+1)

domain

\frac{x ^{2} - 5 x - 6}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = \frac{1}{2} x^{2} + 4 x + 1

y = \frac{e ^{x}}{1 + 5 e ^{x}}

2 sin (\frac{x - π}{3})

f (x) = \frac{2}{x ^{2} + 4}

y = 2 sin (6 x - π)

What is the domain of (x^2-5x-6)/(x+1) ?
The domain of (x^2-5x-6)/(x+1) is x<-1\lor x>-1