What is the domain of f(x)=(3x+1)/(x^2-16) ?

The domain of f(x)=(3x+1)/(x^2-16) is x 4

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domain of f(x)=(3x+1)/(x^2-16)

domain

f (x) = \frac{3 x + 1}{x ^{2} - 16}

x < - 4 or - 4 < x < 4 or x > 4

Interval Notation

(- \infty, - 4) \cup (- 4, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 4

The function domain

x < - 4 or - 4 < x < 4 or x > 4

f (x) = \frac{2 - x}{1 - x}

f (x) = 7 x^{4} - 42 x^{2}

(- 2, 5), (2, - 3)

\frac{x ^{2} - 3 x}{x + 1}

What is the domain of f(x)=(3x+1)/(x^2-16) ?
The domain of f(x)=(3x+1)/(x^2-16) is x<-4\lor-4<x<4\lor x>4