What is the range of f(x)=(2x-25)/(3+x) ?

The range of f(x)=(2x-25)/(3+x) is f(x) 2

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range of f(x)=(2x-25)/(3+x)

range

f (x) = \frac{2 x - 25}{3 + x}

f (x) < 2 or f (x) > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{2 x - 25}{3 + x}

Inverse of

\frac{2 x - 25}{3 + x} : \frac{- 25 - 3 x}{x - 2}

\frac{- 25 - 3 x}{x - 2}

Find the domain of each inverse function

Domain of

\frac{- 25 - 3 x}{x - 2} : x < 2 or x > 2

Combine the intervals

f (x) < 2 or f (x) > 2

f (x) = - \frac{2}{x} - 1

5 sec (x)

3 y = x - 6, (2, - 5)

(- 4, 1), (1, 7)

f (x) = \frac{1}{2} sec (\frac{π x}{2})

What is the range of f(x)=(2x-25)/(3+x) ?
The range of f(x)=(2x-25)/(3+x) is f(x)<2\lor f(x)>2