What is the domain of f(x)=sqrt(4x+9) ?

The domain of f(x)=sqrt(4x+9) is x>=-9/4

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domain of f(x)=sqrt(4x+9)

domain

f (x) = 4 x + 9

x \geq - \frac{9}{4}

Interval Notation

[- \frac{9}{4}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{9}{4}

The function domain

x \geq - \frac{9}{4}

f (x) = - \frac{1}{2} tan (2 π x)

x - 7

f (x) = x^{2} (x + 3)^{2}

f (x) = x^{2} - 10 x + 24

x - ln (x)

What is the domain of f(x)=sqrt(4x+9) ?
The domain of f(x)=sqrt(4x+9) is x>=-9/4