What is the domain of f(x)=sqrt(-40-8x)-4 ?

The domain of f(x)=sqrt(-40-8x)-4 is x<=-5

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domain of f(x)=sqrt(-40-8x)-4

domain

f (x) = - 40 - 8 x - 4

x \leq - 5

Interval Notation

(- \infty, - 5]

Solution steps

Find non-negative values for radicals:

x \leq - 5

The function domain

x \leq - 5

f (x) = (x + 2)^{3} (x - 4)^{4}

y = x - 1

f (x) = 4 x + 9

f (x) = - \frac{1}{2} tan (2 π x)

x - 7

What is the domain of f(x)=sqrt(-40-8x)-4 ?
The domain of f(x)=sqrt(-40-8x)-4 is x<=-5