What is the domain of (sqrt(x^2-1))(1/(x+2)) ?

The domain of (sqrt(x^2-1))(1/(x+2)) is x = 1

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domain of (sqrt(x^2-1))(1/(x+2))

domain

(x^{2} - 1) (\frac{1}{x + 2})

x < - 2 or - 2 < x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 2) \cup (- 2, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x < - 2 or - 2 < x \leq - 1 or x \geq 1

y - 3 = \frac{6}{5} (x - 5)

f (x) = (x - 4)^{3}

y = x^{2} - 2 x + 3

y = 3^{x + 1} - 4

x (x^{2} - 4)

What is the domain of (sqrt(x^2-1))(1/(x+2)) ?
The domain of (sqrt(x^2-1))(1/(x+2)) is x<-2\lor-2<x<=-1\lor x>= 1