What is the domain of f(x)=(x^2+1)/(x-1) ?

The domain of f(x)=(x^2+1)/(x-1) is x 1

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domain of f(x)=(x^2+1)/(x-1)

domain

f (x) = \frac{x ^{2} + 1}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = \frac{3 x - 4}{x ^{2} - 5 x + 10}

f (x) = 10 - x

g (x) = \frac{2 x}{x ^{2} - 9}

f (x) = \frac{x - 2}{2 x - 10}

f (x) = 2 x - 18

What is the domain of f(x)=(x^2+1)/(x-1) ?
The domain of f(x)=(x^2+1)/(x-1) is x<1\lor x>1