What is the domain of f(x)=sqrt(3-6x) ?

The domain of f(x)=sqrt(3-6x) is x<= 1/2

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domain of f(x)=sqrt(3-6x)

domain

f (x) = 3 - 6 x

x \leq \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{1}{2}

The function domain

x \leq \frac{1}{2}

\frac{1}{2 x + 1}

y = - 1.75 (- 6) + 19

ln (sin (x)) \cdot sin (x)

6 x - 48

x + 2 y = 12

What is the domain of f(x)=sqrt(3-6x) ?
The domain of f(x)=sqrt(3-6x) is x<= 1/2