What is the domain of f(x)=sqrt(4x+1)-4 ?

The domain of f(x)=sqrt(4x+1)-4 is x>=-1/4

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domain of f(x)=sqrt(4x+1)-4

domain

f (x) = 4 x + 1 - 4

x \geq - \frac{1}{4}

Interval Notation

[- \frac{1}{4}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{4}

The function domain

x \geq - \frac{1}{4}

\frac{x + 1}{x ^{2} + 1}

3 x - 4 y = 12

f (x) = \frac{x - 3}{( x + 6 ) ( x - 3 )}

(- 1, 3), (2, 0)

f (x) = \frac{2 x + 1}{x ^{2} + 5 x + 6}

What is the domain of f(x)=sqrt(4x+1)-4 ?
The domain of f(x)=sqrt(4x+1)-4 is x>=-1/4