What is the domain of f(x)= x/(sqrt(x^2-3x+2)) ?

The domain of f(x)= x/(sqrt(x^2-3x+2)) is x 2

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domain of f(x)= x/(sqrt(x^2-3x+2))

domain

f (x) = \frac{x}{x ^{2} - 3 x + 2}

x < 1 or x > 2

Interval Notation

(- \infty, 1) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 2

Find undefined (singularity) points:

x = 2, x = 1

Combine real regions and undefined points for final function domain

x < 1 or x > 2

f (x) = \frac{( 2 x + 4 )}{( x ^{2} - 16 )}

\frac{X ^{2} + 3 X - 4}{X ^{4} - X ^{3} + X ^{2} - X}

x - 3 + \frac{2}{x + 1}

x^{2} - 3

f (x) = \frac{x ^{3} + 8}{x ^{2} + 4}

What is the domain of f(x)= x/(sqrt(x^2-3x+2)) ?
The domain of f(x)= x/(sqrt(x^2-3x+2)) is x<1\lor x>2