What is the domain of f(x)=sqrt(3x^2+5x-2) ?

The domain of f(x)=sqrt(3x^2+5x-2) is x = 1/3

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domain of f(x)=sqrt(3x^2+5x-2)

domain

f (x) = 3 x^{2} + 5 x - 2

x \leq - 2 or x \geq \frac{1}{3}

Interval Notation

(- \infty, - 2] \cup [\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq \frac{1}{3}

The function domain

x \leq - 2 or x \geq \frac{1}{3}

x^{4} - 4 x^{3}

y = \frac{2}{x + 3} - 1

f (x) = - \frac{x ^{3}}{3} + 16 x

f (x) = 4 - 2 2 - 4 x

f (x) = \frac{1}{5} cos (3 x)

What is the domain of f(x)=sqrt(3x^2+5x-2) ?
The domain of f(x)=sqrt(3x^2+5x-2) is x<=-2\lor x>= 1/3