What is the asymptotes of f(x)=(x-1)/((2x+1)(x-5)) ?

The asymptotes of f(x)=(x-1)/((2x+1)(x-5)) is Vertical: x=-1/2 ,x=5,Horizontal: y=0

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asymptotes of f(x)=(x-1)/((2x+1)(x-5))

asymptotes

f (x) = \frac{x - 1}{( 2 x + 1 ) ( x - 5 )}

Vertical : x = - \frac{1}{2}, x = 5, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{x - 1}{( 2 x + 1 ) ( x - 5 )} : x = - \frac{1}{2}, x = 5

Horizontal Asymptotes of

\frac{x - 1}{( 2 x + 1 ) ( x - 5 )} : y = 0

Slant Asymptotes of

\frac{x - 1}{( 2 x + 1 ) ( x - 5 )} :

None

Vertical : x = - \frac{1}{2}, x = 5, Horizontal : y = 0

- \frac{2}{3}

f (x) = 3 x + 4 y + 2 z = 24

f (x) = 4 x^{2} + 8 x

lo g_{8} (x)

f (x) = x^{2} e^{- x}

What is the asymptotes of f(x)=(x-1)/((2x+1)(x-5)) ?
The asymptotes of f(x)=(x-1)/((2x+1)(x-5)) is Vertical: x=-1/2 ,x=5,Horizontal: y=0