What is the range of f(x)=sqrt(6-2x) ?

The range of f(x)=sqrt(6-2x) is f(x)>= 0

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range of f(x)=sqrt(6-2x)

range

f (x) = 6 - 2 x

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

\frac{2 x}{x ^{2} + 4}

f (x) = (x - 10)^{2}

f (x) = y^{2} - 2 - y

f (x) = \frac{x - 1}{( 2 x + 1 ) ( x - 5 )}

- \frac{2}{3}