What is the inverse of f(x)=2x^2-4x ?

The inverse of f(x)=2x^2-4x is (4+sqrt(16+8x))/4 ,(4-sqrt(16+8x))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2x^2-4x

inverse

f (x) = 2 x^{2} - 4 x

\frac{4 + 16 + 8 x}{4}, \frac{4 - 16 + 8 x}{4}

Solution steps

y = 2 x^{2} - 4 x

Replace

x

with

y

x = 2 y^{2} - 4 y

Solve for

y, x = 2 y^{2} - 4 y

\frac{4 + 16 + 8 x}{4}, \frac{4 - 16 + 8 x}{4}

(- 15, - 2), (- 6, - 4)

f (x) = 1 + 5 x + x^{2}

f (x) = x + 3 y = 6

(3.9) (14.9)

f (x) = 2 x^{2} + 9

What is the inverse of f(x)=2x^2-4x ?
The inverse of f(x)=2x^2-4x is (4+sqrt(16+8x))/4 ,(4-sqrt(16+8x))/4