What is the extreme f(x)=4+9x^2-6x^3 ?

The extreme f(x)=4+9x^2-6x^3 is Minimum(0,4),Maximum(1,7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=4+9x^2-6x^3

extreme points

f (x) = 4 + 9 x^{2} - 6 x^{3}

Minimum (0, 4), Maximum (1, 7)

Solution steps

f^{'} (x) = - 18 x^{2} + 18 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = 0

into

4 + 9 x^{2} - 6 x^{3} : 4

Minimum (0, 4)

Plug

x = 1

into

4 + 9 x^{2} - 6 x^{3} : 7

Maximum (1, 7)

Minimum (0, 4), Maximum (1, 7)

f (x) = ln (x - 5) + 3

f (x) = \frac{1}{4} x - 12

f (x) = 7 x + 1

y = 4 x^{3} - 48 x - 1

f (x) = x (x - 8)^{3}

What is the extreme f(x)=4+9x^2-6x^3 ?
The extreme f(x)=4+9x^2-6x^3 is Minimum(0,4),Maximum(1,7)