What is the inverse of f(x)=18500(0.49-x^2) ?

The inverse of f(x)=18500(0.49-x^2) is sqrt(-0.00005…x+0.49),-sqrt(-0.00005…x+0.49)

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inverse of f(x)=18500(0.49-x^2)

inverse

f (x) = 18500 (0.49 - x^{2})

- 0.00005 \dots x + 0.49, - - 0.00005 \dots x + 0.49

Solution steps

y = 18500 (0.49 - x^{2})

Replace

x

with

y

x = 18500 (0.49 - y^{2})

Solve for

y, x = 18500 (0.49 - y^{2})

- 0.00005 \dots x + 0.49, - - 0.00005 \dots x + 0.49

(15, - 17), (- 20, - 5)

(0, 7), (- 2, - 1)

f (x) = \frac{( x - 2 ) ^{2}}{x - 1}

y = \frac{4}{x + 7}

f (x) = \frac{- 5 x - 1}{4 x - 4}

What is the inverse of f(x)=18500(0.49-x^2) ?
The inverse of f(x)=18500(0.49-x^2) is sqrt(-0.00005…x+0.49),-sqrt(-0.00005…x+0.49)