What is the critical f(x)=8x^5-5x^4-20x^3 ?

The critical f(x)=8x^5-5x^4-20x^3 is x=-1,x=0,x= 3/2

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critical f(x)=8x^5-5x^4-20x^3

critical points

f (x) = 8 x^{5} - 5 x^{4} - 20 x^{3}

x = - 1, x = 0, x = \frac{3}{2}

Solution steps

8 x^{5} - 5 x^{4} - 20 x^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 0, x = \frac{3}{2}

Identify critical points not in

f (x)

domain

Domain of

8 x^{5} - 5 x^{4} - 20 x^{3} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = \frac{3}{2}

x (x + 1) (x - 2)^{2}

f (x) = \frac{( - x + 1 )}{( x - 3 )}

f (x) = \frac{8 x ^{2}}{x ^{4} + 16}

f (x) = x^{5}

(- 3, 6), (- 6, - 2)

What is the critical f(x)=8x^5-5x^4-20x^3 ?
The critical f(x)=8x^5-5x^4-20x^3 is x=-1,x=0,x= 3/2