What is the critical f(x)=2x^3+3x^2-36x+20 ?

The critical f(x)=2x^3+3x^2-36x+20 is x=-3,x=2

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critical f(x)=2x^3+3x^2-36x+20

critical points

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 20

x = - 3, x = 2

Solution steps

2 x^{3} + 3 x^{2} - 36 x + 20

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 2

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} + 3 x^{2} - 36 x + 20 : - \infty < x < \infty

All critical points are in domain

x = - 3, x = 2

f (x) = 2 sin (2 x + π) + 3

f (x) = 3 x 2 x^{2} + 1

- x^{2} + 8 x - 14

\frac{x}{x ^{2} - 4}

y = 3^{x}

What is the critical f(x)=2x^3+3x^2-36x+20 ?
The critical f(x)=2x^3+3x^2-36x+20 is x=-3,x=2