What is the slope ofintercept x+3y=0 ?

The slope ofintercept x+3y=0 is y=-1/3 x+0

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slope ofintercept x+3y=0

slope intercept

x + 3 y = 0

y = - \frac{1}{3} x + 0

Solution steps

x + 3 y = 0

Convert to slope intercept form:

y = - \frac{1}{3} x

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = - \frac{1}{3} x + 0

- 6

y = \frac{1}{x}

f (x) = \frac{1}{∣ x + 3 ∣}

\frac{1}{3 x - 6}

- 64 - x^{2}

What is the slope ofintercept x+3y=0 ?
The slope ofintercept x+3y=0 is y=-1/3 x+0