What is the critical (x^2-2x+4)/(x-2) ?

The critical (x^2-2x+4)/(x-2) is x=0,x=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical (x^2-2x+4)/(x-2)

critical points

\frac{x ^{2} - 2 x + 4}{x - 2}

x = 0, x = 4

Solution steps

\frac{x ^{2} - 2 x + 4}{x - 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 2 x + 4}{x - 2} : x < 2 or x > 2

\frac{x ^{2} - 2 x + 4}{x - 2}

is not defined at

x = 2

, therefore:

x = 0, x = 4

f (x) = (1 - x)^{2}

f (x) = x^{3} - 6 x^{2} + 12 x - 8

y = \frac{- x ^{2}}{x ^{2} - 2 x + 8}

y = ln (x - 2)

f (x) = \frac{4 x + 5}{x ^{2} - x + 1}

What is the critical (x^2-2x+4)/(x-2) ?
The critical (x^2-2x+4)/(x-2) is x=0,x=4