What is the critical f(x)=t^4-16t^3+64t^2 ?

The critical f(x)=t^4-16t^3+64t^2 is t=0,t=4,t=8

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critical f(x)=t^4-16t^3+64t^2

critical points

f (x) = t^{4} - 16 t^{3} + 64 t^{2}

t = 0, t = 4, t = 8

Solution steps

t^{4} - 16 t^{3} + 64 t^{2}

Find where

f^{'} (t)

is equal to zero or undefined

t = 0, t = 4, t = 8

Identify critical points not in

f (t)

domain

Domain of

t^{4} - 16 t^{3} + 64 t^{2} : - \infty < t < \infty

All critical points are in domain

t = 0, t = 4, t = 8

(2, - 7), (9, - 2)

f (x) = lo g_{5} (x^{3})

- 5, - 2

f (x) = \frac{3 x + 5}{x - 2}

f (x) = \frac{1}{2} x + 1

What is the critical f(x)=t^4-16t^3+64t^2 ?
The critical f(x)=t^4-16t^3+64t^2 is t=0,t=4,t=8