What is the inverse of f(x)=(x-4)/(3x+5) ?

The inverse of f(x)=(x-4)/(3x+5) is (-4-5x)/(3x-1)

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inverse of f(x)=(x-4)/(3x+5)

inverse

f (x) = \frac{x - 4}{3 x + 5}

\frac{- 4 - 5 x}{3 x - 1}

Solution steps

y = \frac{x - 4}{3 x + 5}

Replace

x

with

y

x = \frac{y - 4}{3 y + 5}

Solve for

y, x = \frac{y - 4}{3 y + 5}

\frac{- 4 - 5 x}{3 x - 1}

f (x) = \frac{t + 1}{t ^{2} - t - 2}

f (x) = \frac{4}{4 - 2 x}

\frac{x}{x ^{2} + 2}

f (x) = x^{3} + 8 x^{2} + 15 x

- \frac{2}{x}

What is the inverse of f(x)=(x-4)/(3x+5) ?
The inverse of f(x)=(x-4)/(3x+5) is (-4-5x)/(3x-1)