What is the asymptotes of f(x)=(2x^2+x-1)/(x+4) ?

The asymptotes of f(x)=(2x^2+x-1)/(x+4) is Vertical: x=-4,Slant: y=2x-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(2x^2+x-1)/(x+4)

asymptotes

f (x) = \frac{2 x ^{2} + x - 1}{x + 4}

Vertical : x = - 4, Slant : y = 2 x - 7

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + x - 1}{x + 4} : x = - 4

Horizontal Asymptotes of

\frac{2 x ^{2} + x - 1}{x + 4} :

None

Slant Asymptotes of

\frac{2 x ^{2} + x - 1}{x + 4} : y = 2 x - 7

Vertical : x = - 4, Slant : y = 2 x - 7

f (x) = 5 x^{2} + 7

f (x) = x^{2} - 2 x

f (x) = \frac{1}{x ^{2} - 6 x + 12}

f (x) = x^{2} + 5 x

(x - 2)^{(4)}

What is the asymptotes of f(x)=(2x^2+x-1)/(x+4) ?
The asymptotes of f(x)=(2x^2+x-1)/(x+4) is Vertical: x=-4,Slant: y=2x-7