What is the inverse of f(x)=sqrt(x^2-4x) ?

The inverse of f(x)=sqrt(x^2-4x) is 2+sqrt(x^2+4),2-sqrt(x^2+4)

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inverse of f(x)=sqrt(x^2-4x)

inverse

f (x) = x^{2} - 4 x

2 + x^{2} + 4, 2 - x^{2} + 4

Solution steps

y = x^{2} - 4 x

Replace

x

with

y

x = y^{2} - 4 y

Solve for

y, x = y^{2} - 4 y

2 + x^{2} + 4, 2 - x^{2} + 4

f (x) = (x^{2} - 1)^{2}

f (x) = 8 x - 6 y = - 2

(x + 1)^{2} + 1

- x - 3

f (x) = x - 6 x + 1

What is the inverse of f(x)=sqrt(x^2-4x) ?
The inverse of f(x)=sqrt(x^2-4x) is 2+sqrt(x^2+4),2-sqrt(x^2+4)