What is the inverse of ((x^5)/5-1)^{1/3} ?

The inverse of ((x^5)/5-1)^{1/3} is \sqrt[5]{5x^3+5}

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inverse of ((x^5)/5-1)^{1/3}

inverse

(\frac{x ^{5}}{5} - 1)^{\frac{1}{3}}

Solution steps

y = (\frac{x ^{5}}{5} - 1)^{\frac{1}{3}}

Replace

x

with

y

x = (\frac{y ^{5}}{5} - 1)^{\frac{1}{3}}

Solve for

y, x = (\frac{y ^{5}}{5} - 1)^{\frac{1}{3}}

f (x) = 3 x - 1

\frac{x}{4 - x ^{2}}

f (x) = 3 ln (4 x - 1) + 9

\frac{e ^{x} - e ^{- x}}{6}

f (x) = 2 x^{4}

What is the inverse of ((x^5)/5-1)^{1/3} ?
The inverse of ((x^5)/5-1)^{1/3} is \sqrt[5]{5x^3+5}